2p^2-11p-40=0

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Solution for 2p^2-11p-40=0 equation: 



2p^2-11p-40=0

a = 2; b = -11; c = -40;
Δ = b2-4ac
Δ = -112-4·2·(-40)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$


$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-21}{2*2}=\frac{-10}{4}
=-2+1/2
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+21}{2*2}=\frac{32}{4}
=8
$

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